Advertisements
Advertisements
प्रश्न
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is, increased by 60%.
उत्तर
Increased by = 60%
Resulting mean = 32 + 60% of 32
= `32 + 60/100 xx 32 = 32 + 192/10`
= `32/1 + 19.2/1 = 51.2`
APPEARS IN
संबंधित प्रश्न
Marks obtained by 40 students in a short assessment is given below, where a and b are two missing data.
| Marks | 5 | 6 | 7 | 8 | 9 |
| Number of Students | 6 | a | 16 | 13 | b |
If the mean of the distribution is 7.2, find a and b.
Marks obtained (in mathematics) by 9 student are given below:
60, 67, 52, 76, 50, 51, 74, 45 and 56
if marks of each student be increased by 4; what will be the new value of arithmetic mean.
Attempt this question on graph paper.
| Age (yrs ) | 5-15 | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 | 65-75 |
| No.of casualties | 6 | 10 | 15 | 13 | 24 | 8 | 7 |
(1) Construct the 'less than' Cumulative frequency curve for the above data. using 2 cm =10 years on one axis and 2 cm =10 casualties on the other.
(2)From your graph determine :
(a)the median
(b)the lower quartile
In a malaria epidemic, the number of cases diagnosed were as follows:
| Date July | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
| Num | 5 | 12 | 20 | 27 | 46 | 30 | 31 | 18 | 11 | 5 | 0 | 1 |
On what days do the mode and upper and lower quartiles occur?
Find the mean of the following frequency distribution :
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| Frequency | 4 | 4 | 7 | 10 | 12 | 8 | 5 |
Find the mean of: 12, 9, 6,11 and 17
Find the median of 26, 33, 41, 18, 30, 22, 36, 45 and 24
The median of the data 12, 14, 23, 25, 34, 11, 42, 45, 32, 22, 44 is ___________
If the extreme observations on both the ends of a data arranged in ascending order are removed, the median gets affected.
Find the median of first nine even natural numbers.
