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प्रश्न
Find the mean and the median of: 2, 4, 5, 8, 10,13 and 14
उत्तर
Given data = 2, 4, 5, 8, 10, 13 and 14
Clearly, middle term is 8
∴ Median = 8
∴ Mean = `"sum of observations"/"Number of observations"`
`= (2 + 4 + 5 +8 + 10 + 13 + 14)/7 = 56/7 = 8`
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संबंधित प्रश्न
The ages of 40 students are given in the following table :
| Age (in years) | 12 | 13 | 14 | 15 | 16 | 17 | 18 |
| Frequency | 2 | 4 | 6 | 9 | 8 | 7 | 4 |
Find the arithmetic mean.
The marks obtained by 120 students in a mathematics test is given below:
| Marks | No. of students |
| 0 – 10 | 5 |
| 10 – 20 | 9 |
| 20 – 30 | 16 |
| 30 – 40 | 22 |
| 40 – 50 | 26 |
| 50 – 60 | 18 |
| 60 – 70 | 11 |
| 70 – 80 | 6 |
| 80 – 90 | 4 |
| 90 – 100 | 3 |
Draw an ogive for the given distributions on a graph sheet. Use a suitable scale for your ogive. Use your ogive to estimate:
- the median
- the number of student who obtained more than 75% in test.
- the number of students who did not pass in the test if the pass percentage was 40.
- the lower quartile.
Find the arithmetic mean (correct to the nearest whole number) by using step-deviation method.
| x | 5 | 10 | 15 | 20 | 25 | 30 | 35 | 40 | 45 | 50 |
| f | 20 | 43 | 75 | 67 | 72 | 45 | 39 | 9 | 8 | 6 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
| Marks | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
| No. of boys | 10 | 12 | 14 | 12 | 9 | 7 | 6 |
The median of observations 10, 11, 13, 17, x + 5, 20, 22, 24 and 53 (arranged in ascending order) is 18; find the value of x.
Find the mean of the first six multiples of 5.
Find the mean of: all prime numbers between 20 and 40.
Find the median of 25, 16, 15, 10, 8, 30
The median of any data lies between the ______ and ______ observations.
Median of the data may or may not be from the given data.
