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प्रश्न
The marks obtained by 120 students in a mathematics test is given below:
Marks | No. of students |
0 – 10 | 5 |
10 – 20 | 9 |
20 – 30 | 16 |
30 – 40 | 22 |
40 – 50 | 26 |
50 – 60 | 18 |
60 – 70 | 11 |
70 – 80 | 6 |
80 – 90 | 4 |
90 – 100 | 3 |
Draw an ogive for the given distributions on a graph sheet. Use a suitable scale for your ogive. Use your ogive to estimate:
- the median
- the number of student who obtained more than 75% in test.
- the number of students who did not pass in the test if the pass percentage was 40.
- the lower quartile.
उत्तर
Marks | No. of students | c.f. |
0 – 10 | 5 | 5 |
10 – 20 | 9 | 14 |
20 – 30 | 16 | 30 |
30 – 40 | 22 | 52 |
40 – 50 | 26 | 78 |
50 – 60 | 18 | 96 |
60 – 70 | 11 | 107 |
70 – 80 | 6 | 113 |
80 – 90 | 4 | 117 |
90 – 100 | 3 | 120 |
First of all, we plot the points (0, 0), (10, 5), (20, 14), (30, 30), (40, 52), (50, 78), (60, 96), (70, 107), (80, 113), (90, 117), (100, 120) on graph paper and join them by free hand curve to give the required ogive.
Median = `120/2` = 60.5th term.
i. Through 60.5th marks, draw a line segment parallel to x-axis which meets the curve at A.
From A, draw a line segment perpendicular to, x-axis meeting at B.
∴ B is the median = 43 ...(approx.)
ii. On x-axis, a point P representing 75, drawn vertical line meeting ogive at Q. From Q draw a ⊥ on y-axis meeting y-axis at R, the ordinate of y be 110.
No. of students who obtained upto 75% marks in the test = 110
∴ No. of students who obtained more than 75% = 120 – 110 = 10
iii. No. of students who obtained less than 40% marks in the test = 52 ...(∴ in the graph x = 40, y = 52)
iv. The lower quartile = (Q1)
= `120 xx 1/4`
= 30th term
= 30
From a point B (30) on y-axis, draw a parallel to x-axis meeting the curve at Q and from Q. Draw a line parallel to x-axis meeting it at 30.
∴ Lower Quartile = 30 = Q1.
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संबंधित प्रश्न
The mean of the number 6, ‘y’, 7, ‘x’ and 14 is 8. Express ‘y’ in terms of ‘x’.
Find the mean, median and mode of the following marks obtained by 16 students in a class test marked out of 10 marks:
0, 0, 2, 2, 3, 3, 3, 4, 5, 5, 5, 5, 6, 6, 7 and 8.
For the following set of data, find the median:
10, 75, 3, 81, 17, 27, 4, 48, 12, 47, 9 and 15.
The mean of the following distribution in 52 and the frequency of class interval 30-40 'f' find f
C.I | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
freq | 5 | 3 | f | 7 | 2 | 6 | 13 |
Find the mean (correct to one place of decimal) by using short-cut method.
x |
40 |
41 |
43 |
45 |
46 |
49 |
50 |
f |
14 |
28 |
38 |
50 |
40 |
20 |
10 |
Find the mode of the following:
3, 4, 5, 7, 6, 3, 5, 4, 3, 5, 6, 4, 7, 5, 4, 5, 4, 3, 4, 5, 7, 6, 5, 6, 6, 7
Find the mode of the following:
15, 17, 16, 17, 10, 12, 14, 16, 19, 12, 16, 15, 16
Find the mode of the following frequency distribution:
Variate | 20 | 21 | 22 | 23 | 24 | 25 | 26 |
Frequency | 21 | 20 | 26 | 35 | 22 | 13 | 10 |
Find the median of the following frequency distribution :
Salarv fin Rs) | 3500 | 4000 | 4500 | 5000 | 5500 | 6000 |
No. of people | 9 | 17 | 23 | 15 | 6 | 5 |
The marks obtained by 200 students in an examination are given below :
Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
No.of students | 5 | 10 | 11 | 20 | 27 | 38 | 40 | 29 | 14 | 6 |
Using a graph paper, draw an Ogive for the above distribution. Use your Ogive to estimate:
(i) the median;
(ii) the lower quartile;
(iii) the number of students who obtained more than 80% marks in the examination and
(iv) the number of students who did not pass, if the pass percentage was 35.
Use the scale as 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis.