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प्रश्न
Median of the data may or may not be from the given data.
विकल्प
True
False
उत्तर
This statement is True.
Explanation:
When the given data is arranged in ascending (or descending) order, then the middle most observation is the median of the data.
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संबंधित प्रश्न
Calculate the mean of the distribution given below using the shortcut method.
Marks | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 |
No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
Draw a histogram from the following frequency distribution and find the mode from the graph:
Class | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 | 25-30 |
Frequency | 2 | 5 | 18 | 14 | 8 | 5 |
The following table gives the heights of plants in centimeter. If the mean height of plants is 60.95 cm; find the value of 'f'.
Height (cm) | 50 | 55 | 58 | 60 | 65 | 70 | 71 |
No. of plants | 2 | 4 | 10 | f | 5 | 4 | 3 |
In a school, 100 pupils have heights as tabulate below:
Height (in cm) | No. of pupils |
121 – 130 | 12 |
131 – 140 | 16 |
141 – 150 | 30 |
151 – 160 | 20 |
161 – 170 | 14 |
171 – 180 | 8 |
Find the median height by drawing an ogive.
Find the mean, median and mode of the following marks obtained by 16 students in a class test marked out of 10 marks:
0, 0, 2, 2, 3, 3, 3, 4, 5, 5, 5, 5, 6, 6, 7 and 8.
In a malaria epidemic, the number of cases diagnosed were as follows:
Date July | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Num | 5 | 12 | 20 | 27 | 46 | 30 | 31 | 18 | 11 | 5 | 0 | 1 |
On what days do the mode and upper and lower quartiles occur?
Find the median of all prime numbers between 20 and 50
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
No. of boys | 10 | 12 | 14 | 12 | 9 | 7 | 6 |
Find the mean of first six natural numbers.
Find the median of 26, 33, 41, 18, 30, 22, 36, 45 and 24