Advertisements
Advertisements
प्रश्न
Find the mode and the median of the following frequency distributions.
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
उत्तर
Since the frequency for x = 14 is maximum.
So mode = 14.
x | f | Cumlative Frequency |
10 | 1 | 1 |
11 | 4 | 5 |
12 | 7 | 12 |
13 | 5 | 17 |
14 | 9 | 26 |
15 | 3 | 29 |
N=29 |
Median=`((n+1)/2)^("th")` term
= `(30/2)^("th")` term
= `15^("th")` term
Frequency of the `15^"th"` term
According to the table it can be observed that the value of x from to the `13^"th"` term to the `17^"th"` term is 13.
So the median = 13.
APPEARS IN
संबंधित प्रश्न
Marks obtained (in mathematics) by 9 students are given below:
60, 67, 52, 76, 50, 51, 74, 45 and 56
- Find the arithmetic mean.
- If marks of each student be increased by 4; what will be the new value of arithmetic mean?
The mean of the number 6, ‘y’, 7, ‘x’ and 14 is 8. Express ‘y’ in terms of ‘x’.
A boy scored following marks in various class tests during a term; each test being marked out of 20.
15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16
What are his total marks?
Find the mean of all factors of 10.
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is decreased by 20%.
Mean of 5 numbers is 20 and the mean of the other 5 numbers is 30. Find the mean of all the 10 numbers taken together.
Find the median of 9, 3, 20, 13, 0, 7 and 10
Find the mean and the median of: 2, 4, 5, 8, 10,13 and 14
The measures of central tendency may not lie between the maximum and minimum values of data.
The median of the following observations arranged in ascending order is 64. Find the value of x:
27, 31, 46, 52, x, x + 4, 71, 79, 85, 90