Advertisements
Advertisements
प्रश्न
Find the mode and the median of the following frequency distributions.
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
उत्तर
Since the frequency for x = 14 is maximum.
So mode = 14.
| x | f | Cumlative Frequency |
| 10 | 1 | 1 |
| 11 | 4 | 5 |
| 12 | 7 | 12 |
| 13 | 5 | 17 |
| 14 | 9 | 26 |
| 15 | 3 | 29 |
| N=29 |
Median=`((n+1)/2)^("th")` term
= `(30/2)^("th")` term
= `15^("th")` term
Frequency of the `15^"th"` term
According to the table it can be observed that the value of x from to the `13^"th"` term to the `17^"th"` term is 13.
So the median = 13.
APPEARS IN
संबंधित प्रश्न
Calculate the mean of the distribution given below using the shortcut method.
| Marks | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 |
| No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
The mean of the following frequency distribution is 25.8 and the sum of all the frequencies is 50. Find x and y.
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequency | 7 | x | 15 | y | 10 |
Find the mean of the following frequency distribution by the short cut method :
| Class | 1-10 | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 |
| Frequency | 7 | 10 | 14 | 17 | 15 | 11 | 6 |
Find the mode of the following:
20, 20, 30, 30, 30, 30, 35, 40, 40, 45, 45, 45, 50, 55, 60, 60, 60 ,65, 70, 70, 70
The pocket expenses (per day) of Anuj, during a certain week, from Monday to Saturday were ₹85.40, ₹88.00, ₹86.50, ₹84.75, ₹82.60 and ₹87.25. Find the mean pocket expenses per day.
Find the mean of: 2.1, 4.5, 5.2, 7.1 and 9.3
Find the median of 21, 21, 22, 23, 23, 24, 24, 24, 24, 25 and 25
3, 8, 10, x, 14, 16, 18, 20 are in the ascending order and their median is 13. Calculate the numerical value of x.
Find the median of the given values : 47, 53, 62, 71, 83, 21, 43, 47, 41
Find the median of the 10 observations 36, 33, 45, 28, 39, 45, 54, 23, 56, 25. If another observation 35 is added to the above data, what would be the new median?
