Advertisements
Advertisements
प्रश्न
Find the median of the given values : 47, 53, 62, 71, 83, 21, 43, 47, 41
उत्तर
Arrange the values in ascending order we get
21, 41, 43, 47, 47, 53, 62, 71, 83
The number of values = 9 which is odd
Median = `((9 + 1)/2)^"th"` variable
= `(10/2)^"th"` variable
= 5th variable
∴ Median = 47
APPEARS IN
संबंधित प्रश्न
Draw a histogram from the following frequency distribution and find the mode from the graph:
Class | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 | 25-30 |
Frequency | 2 | 5 | 18 | 14 | 8 | 5 |
Find the mode of the following data:
7, 9, 8, 7, 7, 6, 8, 10, 7 and 6
Find the mean of the following frequency distribution by the step deviation method :
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 | 120-140 |
Frequency | 12 | 24 | 52 | 88 | 66 | 42 | 16 |
The rainfall (in mm) in a city on 7 days of a certain week is recorded as follows:
Day: | Mon | Tue | Wed | Thus | Fri | Sat | Sun |
Rainfall (in mm): | 0.5 | 2.7 | 2.6 | 0.5 | 2 | 5.8 | 1.5 |
Find the total and average (mean) rainfall for the week.
Find the mean of 35, 44, 31, 57, 38, 29, 26,36, 41 and 43.
Find the mean and the median of: 10,12, 12, 15, 15, 17, 18, 18, 18 and 19
The median of the data 12, 14, 23, 25, 34, 11, 42, 45, 32, 22, 44 is ___________
The median of first ten even natural numbers is ___________
The median class for the given distribution is:
Class Interval | 1 - 5 | 6 - 10 | 11 - 15 | 16 - 20 |
Cumulative Frequency | 2 | 6 | 11 | 18 |
The median of any data lies between the ______ and ______ observations.