मराठी

The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median. - Mathematics

Advertisements
Advertisements

प्रश्न

The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median.

बेरीज

उत्तर

Mean = `"Sum of all observations"/"Total number of observations"`

∴ `68 = (45 + 52 + 60 + x + 69 + 70 + 26 + 81 + 94)/9`

`=> 68 = (497 + x)/9`

`=>` 612 = 497 + x

`=>` x = 612 – 497

`=>` x = 115

Data in ascending order

26, 45, 52, 60, 69, 70, 81, 94, 115

Since the number of observations is odd, the median is the `((n + 1)/2)^(th)` observation

`=>` Median = `((9 + 1)/2)^(th)` observation = 5th observation.

Hence, the median is 69

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 24: Measure of Central Tendency(Mean, Median, Quartiles and Mode) - Exercise 24 (E) [पृष्ठ ३७७]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
पाठ 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (E) | Q 20 | पृष्ठ ३७७

व्हिडिओ ट्यूटोरियलVIEW ALL [4]

संबंधित प्रश्‍न

The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table:

Length (in mm) Number of leaves
118 − 126
127 – 135 5
136 − 144 9
145 – 153 12
154 – 162 5
163 – 171 4
172 – 180 2

Find the median length of the leaves.

(Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 − 126.5, 126.5 − 135.5… 171.5 − 180.5)


A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.

Age (in years) Number of policy holders
Below 20 2
20 - 25 4
25 - 30 18
30 - 35 21
35 - 40 33
40 - 45 11
45 - 50 3
50 - 55 6
55 - 60 2

The following is the distribution of the size of certain farms from a taluka (tehasil):

Size of Farms
(in acres)
Number of Farms
5 – 15 7
15 – 25 12
25 – 35 17
35 – 45 25
45 – 55 31
55 – 65 5
65 – 75 3

Find median size of farms.


For a certain frequency distribution, the values of mean and median are 72 and 78 respectively. Find the value of mode.


Compute the median for the following data:

Marks No. of students
More than 150 0
More than 140 12
More than 130 27
More than 120 60
More than 110 105
More than 100 124
More than 90 141
More than 80 150

Given below is the number of units of electricity consumed in a week in a certain locality:

Class 65 – 85 85 – 105 105 – 125 125 – 145 145 – 165 165 – 185 185 – 200
Frequency 4 5 13 20 14 7 4

Calculate the median.


Find the correct answer from the alternatives given.

Distance Covered per litre (km) 12 - 14 14 - 16 16 - 18 18 - 20
No. of cars 11 12 20 7

The median of the distances covered per litre shown in the above data is in the group . . . . . .

 

The prices of different articles and demand for them is shown in the following frequency distribution table. Find the median of the prices.

Price (Rupees)
20 less than 20 – 40 40 – 60 60 – 80 80 – 100
No. of articles 140 100 80 60 20

If 35 is removed from the data, 30, 34, 35, 36, 37, 38, 39, 40 then the median increases by ______.


The median of the following frequency distribution is 25. Find the value of x.

Class: 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency: 6 9 10 8 x

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×