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Find the moment of inertia of a hydrogen molecule about an axis passing through its centre of mass and perpendicular to the inter-atomic axis. Given: mass of hydrogen atom 1.7 × 10-27 kg - Physics

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प्रश्न

Find the moment of inertia of a hydrogen molecule about an axis passing through its centre of mass and perpendicular to the inter-atomic axis. Given: mass of hydrogen atom 1.7 × 10-27 kg and interatomic distance is equal to 4 × 10-10 m.

योग

उत्तर

Given,

Inter-atomic distance : 4 x 10-10 m

Mass of H2 atom : 1.7 x 10-27 kg

Moment of inertia of H2

= 2M`(R/2)^2 = 1/2 MR^2`

= `1/2 xx 1.7 xx 10^-27 xx 16 xx 10^-20`

= `1.89 xx 10^-46` kg m2.

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Moment of Inertia
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Motion of System of Particles and Rigid Bodies - Evaluation [पृष्ठ २६३]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 5 Motion of System of Particles and Rigid Bodies
Evaluation | Q IV. 6. | पृष्ठ २६३
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