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Question
Find the moment of inertia of a hydrogen molecule about an axis passing through its centre of mass and perpendicular to the inter-atomic axis. Given: mass of hydrogen atom 1.7 × 10-27 kg and interatomic distance is equal to 4 × 10-10 m.
Solution
Given,
Inter-atomic distance : 4 x 10-10 m
Mass of H2 atom : 1.7 x 10-27 kg
Moment of inertia of H2 =
= 2M`(R/2)^2 = 1/2 MR^2`
= `1/2 xx 1.7 xx 10^-27 xx 16 xx 10^-20`
= `1.89 xx 10^-46` kg m2.
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