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प्रश्न
Find the odd man out:
विकल्प
Force responsible for a string to become taut on stretching
Weight of an object
The force due to which we can hold an object in hand.
उत्तर
Force responsible for a string to become taut on stretching, Weight of an object, The force due to which we can hold an object in hand - Weight of an object.
Reason: Weight of an object (force due to gravity) is a non-contact force while force responsible for a string to become taut (tension force) and force due to which we can hold an object in hand (normal force) are contact forces
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संबंधित प्रश्न
Answer the following question.
In the following table, every entry on the left column can match with any number of entries on the right side. Pick up all those and write respectively against A, B, C and D.
| Name of the force | Type of the force | ||
| A | Force due to tension in a string | P | EM force |
| B | Normal force | Q | Reaction force |
| C | Frictional force | R | Conservative force |
| D | Resistive force offered by air or water for objects moving through it. | S | Non-conservative force |
Answer the following question.
Distinguish between real and pseudo force.
Answer the following question.
Distinguish between conservative and nonconservative forces.
Answer the following question.
State the formula for calculating work done by a force. Are there any conditions or limitations in using it directly? If so, state those clearly. Is there any mathematical way out for it? Explain.
Solve the following problem.
As I was standing on a weighing machine inside a lift it recorded 50 kg wt. Suddenly for a few seconds, it recorded 45 kg wt. What must have happened during that time? Explain with complete numerical analysis.
Solve the following problem.
Power is the rate of doing work or the rate at which energy is supplied to the system. A constant force F is applied to a body of mass m. Power delivered by the force at time t from the start is proportional to ______.
Derive the expression for power in terms of F, m, and t.
Solve the following problem.
Derive the expression for power in terms of F, m, and t.
Solve the following problem.
Two galaxies of masses 9 billion solar mass and 4 billion solar mass are 5 million light-years apart. If, the Sun has to cross the line joining them, without being attracted by either of them, through what point it should pass?
Variation of a force in a certain region is given by F = 6x2 – 4x – 8. It displaces an object from x = 1 m to x = 2 m in this region. Calculate the amount of work done.
Solve the following problem.
In the following table, every item on the left side can match with any number of items on the right-hand side. Select all those.
| Types of collision | Illustrations | ||
| a. | Elastic collision | i. | A ball hit by a bat. |
| b. | Inelastic collision | ii. | Molecular collisions responsible for pressure exerted by a gas. |
| c. | Perfectly inelastic collision | iii. | A stationary marble A is hit by marble B and the marble B comes to rest. |
| d. | Head-on collision | iv. | A blob of clay dropped on the ground sticks to the ground. |
| v. | Out of anger, giving a kick to a wall. | ||
| vi. | A striker hits the boundary of a carrom board in a direction perpendicular to the boundary and rebounds. | ||
Two spheres of masses m and M are situated in air and the gravitational force between them is F. The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be ______
Two particles of mass m1 and m2, approach each other due to their mutual gravitational attraction only. Then ______.
A body of mass 'm' begins to move under the action of time-dependent force `vec"F" = ("t"hat"i" + 2"t"^2hat"j")`N where `hat"i" and hat"j"` are unit vectors along x and y axis respectively. The power developed by the force in watt at time 't' is ______.
A force F = (10 + 0.5 x) N acts on a particle in the x-direction. The work done by the force in displacing the particle from x = 0 to x = 2 metre is ______.
A Diwali cracker releases 25 gram gas per second, with a speed of 400 ms-1 after explosion. The force exerted by gas on the cracker is ______.
A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x = 0 to x = 6 m is ______.
Two rods of same length and transfer a given amount of heat 12 second, when they are joined as shown in figure (i), But when they are joined as shown in figure (ii), then they will transfer same heat in same conditions in ______.
A gardener pushes a lawn roller through a distance of 20 m. If he applies a force of 30 kg-wt in a direction inclined at 60° to the ground, the work done by the gardener in pushing the roller is ______.
`["g" = 9.8 "m""/""s"^2, sin30^circ = cos60^circ = 1/2, cos30^circ = sin60^circ = sqrt3/2]`
Which of the following statements is correct?
