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प्रश्न
Find the square of 2x − 3y + z
योग
उत्तर
(2x − 3y + z)2 = (2x)2 + (−3y)2 + (z)2 + 2 × 2x × −3y + 2(−3y) × z + 2 × z × 2x
= 4x2 + 9y2 + z2 − 12xy − 6yz + 4zx
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