Advertisements
Advertisements
प्रश्न
Find the square of `"x"+1/"x"-1`
योग
उत्तर
`("x"+1/"x"-1)^2=("x")^2+(1/"x")^2+(-1)^2+2xx"x"xx1/ "x"+2xx1/"x"xx(-1)+2(-1)xx"x"`
`="x"^2+1/"x"^2+1+2-2/"x"-2"x"`
`="x"^2+1/"x"^2+3-2/"x"-2"x"`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the square of `2"x"+1/"x"+1`
Find the square of `5-x+2/x`
Evaluate using the expansion of (a + b)2 or (a – b)2 :
(9.4)2
Write the place value of the underlined digit.
14,95,210
The expanded form of the number is given. Write the number.
9,00,000 + 20,000 + 7000 + 800 + 5
Write the following numbers in expanded from.
36,01,478
Write the following numbers in expanded from.
28,48,387
Find the face value and place value of the digits coloured in the given numbers.
2010
Find the face value and place value of the digits coloured in the given numbers.
4038
Write in expanded form:
74836
