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प्रश्न
Find the square of `5"x"+1/(5"x")`
योग
उत्तर
`(5"x"+1/(5"x"))^2=(5"x")^2+1/(5"x")^2+2xx5"x"xx1/(5"x")`
`=25"x"^2+1/(25"x"^2)+2`
`=25"x"^2+2+1/(25"x"^2)`
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