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प्रश्न
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
उत्तर
(2x2 + xy − y2) + (− x2 + 2xy + 3y2) + (3x2 − 10xy + 4y2)
= 2x2 + xy − y2 − x2 + 2xy + 3y2 + 3x2 − 10xy + 4y2
= 2x2 + 3x2 − x2 + xy + 2xy − 10xy + 3y2 + 4y2 − y2
= 5x2 − x2 + 3xy − 10xy + 7y2 − y2
= 4x2 − 7xy + 6y2
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संबंधित प्रश्न
Subtract the first term from the second:
3.5abc, 10.5abc
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Evaluate:
(8a + 15b) − (3b − 7a)
Evaluate:
(6y − 13) − (4 − 7y)
Subtract:
4x − 6y + 3z from 12x + 7y − 21z.
By how much should x + 2y – 3z be increased to get 3x?
Fill in the blanks:
15 × 3 = .............. and 15x × 3x5y2 = ............
Fill in the blank:
x × 2x2 × 3x3 = .....................
Fill in the blank:
− 8x × − 3x = − ....................
