Advertisements
Advertisements
Question
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
Solution
(2x2 + xy − y2) + (− x2 + 2xy + 3y2) + (3x2 − 10xy + 4y2)
= 2x2 + xy − y2 − x2 + 2xy + 3y2 + 3x2 − 10xy + 4y2
= 2x2 + 3x2 − x2 + xy + 2xy − 10xy + 3y2 + 4y2 − y2
= 5x2 − x2 + 3xy − 10xy + 7y2 − y2
= 4x2 − 7xy + 6y2
APPEARS IN
RELATED QUESTIONS
Evaluate:
7 − (4a − 5)
Evaluate:
(6y − 13) − (4 − 7y)
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
By how much should x + 2y – 3z be increased to get 3x?
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
6 × 3 = .............. and 6x2 × 3x3 = ............
Fill in the blanks:
12 × 4 = .............. and 12ax2 × 4ax = ............
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
6 × 6x2 × 6x2y2 = ...................
Fill in the blank:
5x × 2x2y × (− 7y3) × 2x3y2 = ...............
