Advertisements
Advertisements
Question
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Sum
Solution
(3a2 + 2ab − b2) − (2a2 + 3b2)
= 3a2 + 2ab − b2 − 2a2 − 3b2
= 3a2 − 2a2 + 2ab − b2 − 3b2
= a2 + 2ab − 4b2
shaalaa.com
Algebra Terminology - Literal Numbers, Terms, Expressions, Factor, Coefficient, Polynomials, Degree, like and Unlike Terms
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Evaluate:
(6y − 13) − (4 − 7y)
Subtract:
4x − 6y + 3z from 12x + 7y − 21z.
Take − ab + bc − ca from bc − ca + ab.
Take 5x + 6y − 3z from 3x + 5y − 4z.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
Fill in the blanks:
5 × 4 = .............. and 5x × 4y = ............
Fill in the blank:
3ab × 6ax = ..................
Fill in the blank:
− 5 × − 3x × 5x2 = ..................