Advertisements
Advertisements
प्रश्न
Find the sum of first 1000 positive integers.
Activity :- Let 1 + 2 + 3 + ........ + 1000
Using formula for the sum of first n terms of an A.P.,
Sn = `square`
S1000 = `square/2 (1 + 1000)`
= 500 × 1001
= `square`
Therefore, Sum of the first 1000 positive integer is `square`
उत्तर
Let 1 + 2 + 3 + ........ + 1000
Using formula for the sum of first n terms of an A.P.,
Sn = `"n"/2 ("t"_1 + "t"_"n")`
S1000 = `1000/2 (1 + 1000)`
= 500 × 1001
= 500500
Therefore, Sum of the first 1000 positive integer is 500500.
APPEARS IN
संबंधित प्रश्न
An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term of the A.P.
Find the sum of first 15 multiples of 8.
Find the sum of the first 25 terms of an A.P. whose nth term is given by an = 7 − 3n
Find the sum of all odd natural numbers less than 50.
The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. Find these terms
If (2p +1), 13, (5p -3) are in AP, find the value of p.
Find the sum of all multiples of 9 lying between 300 and 700.
Find four consecutive terms in an A.P. whose sum is 12 and sum of 3rd and 4th term is 14.
(Assume the four consecutive terms in A.P. are a – d, a, a + d, a +2d)
Find the sum \[7 + 10\frac{1}{2} + 14 + . . . + 84\]
Mark the correct alternative in each of the following:
If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is
If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn, then S3n : Sn is equal to
The sum of n terms of an A.P. is 3n2 + 5n, then 164 is its
Let the four terms of the AP be a − 3d, a − d, a + d and a + 3d. find A.P.
Q.5
Q.7
Find the value of x, when in the A.P. given below 2 + 6 + 10 + ... + x = 1800.
The sum of first 16 terms of the AP: 10, 6, 2,... is ______.
The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms.
Find the middle term of the AP. 95, 86, 77, ........, – 247.
Solve the equation:
– 4 + (–1) + 2 + 5 + ... + x = 437
