Advertisements
Advertisements
प्रश्न
Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………
उत्तर
The given A.P. is 8, 3, –2, ………
Here, a = 8, d = 3 – 8 = –5 and n = 22
∴ `S = n/2[2a + (n - 1)d]`
= `22/2 [2 xx 8 + (22 - 1) xx (-5)]`
= 11[16 + 21 × (–5)]
= 11[16 – 105]
= 11 × (–89)
= –979
APPEARS IN
संबंधित प्रश्न
In an A.P., if S5 + S7 = 167 and S10=235, then find the A.P., where Sn denotes the sum of its first n terms.
The sum of three numbers in A.P. is –3, and their product is 8. Find the numbers
Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667.
Find the middle term of the AP 6, 13, 20, …., 216.
Find the sum of the following Aps:
9, 7, 5, 3 … to 14 terms
The next term of the A.P. \[\sqrt{7}, \sqrt{28}, \sqrt{63}\] is ______.
If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
The sum of the first three terms of an Arithmetic Progression (A.P.) is 42 and the product of the first and third term is 52. Find the first term and the common difference.
Find the sum of first 20 terms of an A.P. whose nth term is given as an = 5 – 2n.