Advertisements
Advertisements
Question
Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………
Solution
The given A.P. is 8, 3, –2, ………
Here, a = 8, d = 3 – 8 = –5 and n = 22
∴ `S = n/2[2a + (n - 1)d]`
= `22/2 [2 xx 8 + (22 - 1) xx (-5)]`
= 11[16 + 21 × (–5)]
= 11[16 – 105]
= 11 × (–89)
= –979
APPEARS IN
RELATED QUESTIONS
Determine the A.P. whose 3rd term is 16 and the 7th term exceeds the 5th term by 12.
Find the sum of the first 40 positive integers divisible by 5
Show that `(a-b)^2 , (a^2 + b^2 ) and ( a^2+ b^2) ` are in AP.
If the seventh term of an A.P. is \[\frac{1}{9}\] and its ninth term is \[\frac{1}{7}\] , find its (63)rd term.
The sum of the first n terms of an A.P. is 4n2 + 2n. Find the nth term of this A.P.
If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is
If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn, then S3n : Sn is equal to
Find the sum of first 10 terms of the A.P.
4 + 6 + 8 + .............
Find the sum of first 20 terms of an A.P. whose first term is 3 and the last term is 57.
In an A.P. (with usual notations) : given d = 5, S9 = 75, find a and a9