Advertisements
Advertisements
प्रश्न
Find the value of each angle of an octagon if two of its angles are 148° and 152° and the remaining angles are all equal.
उत्तर
An octagon has 8 sides.
∴ Sum of interior angles
= (n - 2) x 180°
= (8 - 2) x 180°
= 6 x 180°
= 1080°
Given, six of its angles are equal.
Let the equal angles be x each.
148° + 152° + x + x + x + x + x + x = 1080°
⇒ 6x + 300° = 1080°
⇒ 6x = 780°
⇒ x = 130°
Each of the equal angles are equal to 130°.
APPEARS IN
संबंधित प्रश्न
Find the measure of each interior angle of a regular polygon of: 10 sides
Find the measure of each interior angle of a regular polygon of: 15 sides
Find each exterior angle of a regular polygon of: 9 sides
Find the number of sides in a regular polygon, when each interior angle is: 140°
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
In a polygon, there are 3 right angles and the remaining angles are equal to 165°. Find the number of sides in the polygon.
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
