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प्रश्न
Find the value of the polynomial f(y) = 6y – 3y2 + 3 at y = 0
योग
उत्तर
When y = 0
f(y) = 6y – 3y2 + 3
f(0) = 6(0) – 3(0)2 + 3
= 0 – 0 + 3
= 3
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Value of a Polynomial
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अध्याय 3: Algebra - Exercise 3.2 [पृष्ठ ९१]
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