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प्रश्न
Find the value of w, given that x = 3, y = 4, z = – 2 and w = x2 – y2 + z2 – xyz
योग
उत्तर
Given: x = 3, y = 4 and z = – 2
w = x2 – y2 + z2 – xyz
w = 32 – 42 + (– 2)2 – (3)(4)(– 2)
w = 9 – 16 + 4 + 24
w = 37 – 16
w = 21
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