Advertisements
Advertisements
प्रश्न
Simplify and find the degree of 6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
उत्तर
6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
= 6x2 + 1 – [8x – {3x2 – 7 – 4x2 – 2x + 5x + 9}]
= 6x2 + 1 – [8x – {3x2 + 7 + 4x2 – 2x + 5x + 9}]
= 6x2 – 1 – [8x + 3x2 – 7 – 4x2 + 2x – 5x – 9]
= 6x2 + 3x2 – 4x2 – 8x + 2x – 5x – 1 – 7 – 9
= x2(6 + 3 – 4) + x(8 + 2 – 5) – 15
= 5x2 – 11x – 15
Degree of the expression is 2.
APPEARS IN
संबंधित प्रश्न
The degree of the term a3b2c4d2 is ___________
The degree of m2n and mn2 are equal
Find the degree of the following terms.
−7ab
Find the degree of the following expression.
x3 – 1
Find the degree of the following expression.
u5 + u4v + u3v2 + u2v3 + uv4
Simplify and find the degree of the following expression.
10x2 – 3xy + 9y2 – (3x2 – 6xy – 3y2)
Simplify and find the degree of the following expression.
9a4 – 6a3 – 6a4 – 3a2 + 7a3 + 5a2
The degree of 6x7 – 7x3 + 4 is
Find the value of w, given that x = 3, y = 4, z = – 2 and w = x2 – y2 + z2 – xyz
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find the perimeter and the degree of the expression
