Advertisements
Advertisements
प्रश्न
Simplify and find the degree of 6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
उत्तर
6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
= 6x2 + 1 – [8x – {3x2 – 7 – 4x2 – 2x + 5x + 9}]
= 6x2 + 1 – [8x – {3x2 + 7 + 4x2 – 2x + 5x + 9}]
= 6x2 – 1 – [8x + 3x2 – 7 – 4x2 + 2x – 5x – 9]
= 6x2 + 3x2 – 4x2 – 8x + 2x – 5x – 1 – 7 – 9
= x2(6 + 3 – 4) + x(8 + 2 – 5) – 15
= 5x2 – 11x – 15
Degree of the expression is 2.
APPEARS IN
संबंधित प्रश्न
Degree of the constant term is ______________
Find the degree of the following terms.
5x2
Add and find the degree of the following expressions.
(9x + 3y) and (10x – 9y)
Add and find the degree of the following expressions.
(k2 – 25k + 46) and (23 – 2k2 + 21k)
Add and find the degree of the following expressions.
(3m2n + 4pq2) and (5nm2 – 2q2p)
The degree of 6x7 – 7x3 + 4 is
If p(x) and q(x) are two expressions of degree 3, then the degree of p(x) + q(x) is
Identify the degree of the expression, 2a3bc + 3a3b + 3a3c – 2a2b2c2
Find the degree of (2a2 + 3ab – b2) – (3a2 – ab – 3b2)
Find the value of w, given that x = 3, y = 4, z = – 2 and w = x2 – y2 + z2 – xyz
