Advertisements
Advertisements
प्रश्न
Find the degree of (2a2 + 3ab – b2) – (3a2 – ab – 3b2)
उत्तर
(2a2 + 3ab – b2) – (3a2 – ab – 3b2)
= (2a2 + 3ab – b2) + (– 3a2 + ab + 3b2)
= 2a2 + 3ab – b2 – 3a2 + ab + 3b2
= 2a2 – 3a2 + 3ab + ab + 3b2 – b2
= 2a2 – 3a2 + ab(3 + 1) + b2(3 – 1)
= – a2 + 4ab + 2b2
Hence degree of the expression is 2.
APPEARS IN
संबंधित प्रश्न
Degree of the constant term is ______________
The degree of the expression −4x2 yz is −4
Find the degree of the following terms.
5x2
Find the degree of the following terms.
−125
Find the degree of the following expression.
3x2 + 2x + 1
Find the degree of the following expression.
5 – 9y + 15y2 – 6y3
Simplify and find the degree of the following expression.
9a4 – 6a3 – 6a4 – 3a2 + 7a3 + 5a2
If p(x) and q(x) are two expressions of degree 3, then the degree of p(x) + q(x) is
Find the value of w, given that x = 3, y = 4, z = – 2 and w = x2 – y2 + z2 – xyz
Simplify and find the degree of 6x2 + 1 – [8x – {3x2 – 7 – (4x2 – 2x + 5x + 9)}]
