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Question
Find the degree of (2a2 + 3ab – b2) – (3a2 – ab – 3b2)
Solution
(2a2 + 3ab – b2) – (3a2 – ab – 3b2)
= (2a2 + 3ab – b2) + (– 3a2 + ab + 3b2)
= 2a2 + 3ab – b2 – 3a2 + ab + 3b2
= 2a2 – 3a2 + 3ab + ab + 3b2 – b2
= 2a2 – 3a2 + ab(3 + 1) + b2(3 – 1)
= – a2 + 4ab + 2b2
Hence degree of the expression is 2.
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