Advertisements
Advertisements
Question
Add and find the degree of the following expressions.
(k2 – 25k + 46) and (23 – 2k2 + 21k)
Solution
(k2 – 25k + 46) and (23 – 2k2 + 21k)
This can be written as (k2 – 25k + 46) + (23 – 2k2 + 21k)
Grouping the like terms, we get
(k2 – 2k2) + (– 25k + 21k) + (46 + 23)
= k2(1 – 2) + k(– 25 + 21) + 69
= –1k2 – 4k + 69
Thus degree of the expression is 2.
APPEARS IN
RELATED QUESTIONS
The degree of m2n and mn2 are equal
The degree of the expression −4x2 yz is −4
Find the degree of the following terms.
−7ab
Find the degree of the following expression.
3x2 + 2x + 1
Add and find the degree of the following expressions.
(9x + 3y) and (10x – 9y)
Simplify and find the degree of the following expression.
10x2 – 3xy + 9y2 – (3x2 – 6xy – 3y2)
Simplify and find the degree of the following expression.
9a4 – 6a3 – 6a4 – 3a2 + 7a3 + 5a2
If p(x) and q(x) are two expressions of degree 3, then the degree of p(x) + q(x) is
Identify the degree of the expression, 2a3bc + 3a3b + 3a3c – 2a2b2c2
Find the degree of (2a2 + 3ab – b2) – (3a2 – ab – 3b2)
