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प्रश्न
Find the value of x if
`|(x^2 - x + 1, x + 1),(x + 1, x + 1)|` = 0
उत्तर
`|(x^2 - x + 1, x + 1),(x + 1, x + 1)|` = 0
∴ (x2 – x + 1)(x + 1) – (x + 1)(x + 1) = 0
∴ (x + 1)[x2 – x + 1 – x – 1) = 0
∴ (x + 1)(x2 – 2x) = 0
∴ x (x + 1)(x – 2) = 0
∴ x = 0 or x + 1 = 0 or x – 2 = 0
∴ x = 0, x = – 1, x = 2.
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