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प्रश्न
Find x and y if `|(4"i", "i"^3, 2"i"),(1, 3"i"^2, 4),(5, -3, "i")|` = x + iy where i2 = – 1
उत्तर
`|(4"i", "i"^3, 2"i"),(1, 3"i"^2, 4),(5, -3, "i")|`
= `|(4"i", "i"^3, 2"i"),(1, 3"i"^2, 4),(5, -3, "i")|` ...[∵ i2 = -1]
= `4"i"|(3, 4),(-3, "i")|(-"i")|(1, 4),(5, "i")| + 2"i"|(1, 3),(5, -3)|`
4i (-3i + 12) + i(i – 20) + 2i( – 3 + 15)
= 12i2 + 48i + i2 - 20i + 24i
= -11i2 + 52i
= -11(-1) + 52i ...[∵ i2 = -1]
= 11 + 52i
Comparing with x + iy, we get x = 11, y = 52
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