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प्रश्न
Find x.
`(- 1/7)^-5 ÷ (- 1/7)^-7 = (-7)^x`
योग
उत्तर
Using law of exponents, am ÷ an = (a)m – n ...[∵ a is non-zero integer]
Then, `(- 1/7)^(-5 + 7) = (-7)^x`
⇒ `(- 1/7)^2 = (- 7)^x`
⇒ (–7)–2 = (–7)x
On comapring powers of (–7), we get x = –2
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Exponents and Powers - Exercise [पृष्ठ २७४]
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