Advertisements
Advertisements
प्रश्न
Find x.
`((-6)/7)^(x - 7) = 1`
उत्तर
We have, `((-6)/7)^(x - 7) = 1`
Using law of exponents, x0 = 1 ...[∵ a is non-zero integer]
Then, `((-6)/7)^(x - 7) = 1`
It is possible only, if x = 7.
So, `((-6)/7)^(7 - 7) = 1`
⇒ `((-6)/7)^0 = 1` ...[∵ a0 = 1]
Hence, x = 7
APPEARS IN
संबंधित प्रश्न
For any two non-zero rational numbers x and y, x4 ÷ y4 is equal to ______.
(–5)–2 × (–5)–3 = (–5)–6
ap × bq = (ab)pq
Find the value of x so that (–2)3 × (–2)–6 = (–2)2x – 1
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
An electron’s mass is approximately 9.1093826 × 10–31 kilograms. What is this mass in grams?
Use the properties of exponents to verify that statement is true.
`4^(n - 1) = 1/4(4)^n`
Fill in the blanks
Find a single machine that will do the same job as the given hook-up.
a (× 599) machine followed by a (5–100) machine.
Find x.
`(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`
