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प्रश्न
Following are the marks obtained by 9 students in a mathematics test: 50, 69, 20, 33, 53, 39, 40, 65, 59
The mean deviation from the median is ______.
विकल्प
9
10.5
12.67
14.76
MCQ
रिक्त स्थान भरें
उत्तर
The mean deviation from the median is 12.67.
Explanation:
Marks obtained are 50, 69, 20, 33, 53, 39, 40, 65 and 59
Let us write in ascending order
20, 33, 39, 40, 50, 53, 59, 65, 69.
Here n = 9
∴ Median = `(9 + 1)/2` th term = 5th term i.e. 50
∴ Median = 50
Now
`x_i` | `d_i = |x_i = Med|` |
20 | 30 |
33 | 17 |
39 | 11 |
40 | 10 |
50 | 0 |
53 | 3 |
59 | 9 |
65 | 15 |
69 | 19 |
Total | `sumd_i` = 114 |
n = 9 and `sumd_i` = 144
∴ M.D. = `(sumd_i)/n`
= `114/9`
= 12.67
shaalaa.com
Central Tendency - Median
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