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NCERT Exemplar solutions for Mathematics [English] Class 11 chapter 15 - Statistics [Latest edition]

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NCERT Exemplar solutions for Mathematics [English] Class 11 chapter 15 - Statistics - Shaalaa.com
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Solutions for Chapter 15: Statistics

Below listed, you can find solutions for Chapter 15 of CBSE NCERT Exemplar for Mathematics [English] Class 11.


Solved ExamplesExercise
Solved Examples [Pages 272 - 277]

NCERT Exemplar solutions for Mathematics [English] Class 11 15 Statistics Solved Examples [Pages 272 - 277]

Short Answer

Solved Examples | Q 1 | Page 272

Find the mean deviation about the mean of the following data:

Size (x): 1 3 5 7 9 11 13 15
Frequency (f): 3 3 4 14 7 4 3 4
Solved Examples | Q 2 | Page 273

Find the variance and standard deviation for the following data: 57, 64, 43, 67, 49, 59, 44, 47, 61, 59

Solved Examples | Q 3 | Page 273

Show that the two formulae for the standard deviation of ungrouped data.

`sigma = sqrt((x_i - barx)^2/n)` and `sigma`' = `sqrt((x^2_i)/n - barx^2)` are equivalent.

Solved Examples | Q 4 | Page 274

Calculate variance of the following data:

Class interval Frequency
4 – 8 3
8 – 12 6
12 – 16 4
16 – 20 7

Mean `(barx) = (f_ix_i)/(f_i) = (3 xx 6 + 6 xx 10 + 4 xx 14 + 7 xx 18)/20` = 13

Long Answer

Solved Examples | Q 5 | Page 274

Calculate mean, variation and standard deviation of the following frequency distribution:

Classes Frequency
1 – 10 11
10 – 20 29
20 – 30 18
30 – 40 4
40 – 50 5
50 – 60 3
Solved Examples | Q 6 | Page 276

Life of bulbs produced by two factories A and B are given below:

Length of life
(in hours)
Factory A
(Number of bulbs)
Factory B
(Number of bulbs)
550 – 650 10 8
650 – 750 22 60
750 – 850 52 24
850 – 950 20 16
950 – 1050 16 12
  120 120

The bulbs of which factory are more consistent from the point of view of length of life?

Objective Type Questions from 7 to 9

Solved Examples | Q 7 | Page 277

The mean deviation of the data 2, 9, 9, 3, 6, 9, 4 from the mean is ______.

  • 2.23

  • 2.57

  • 3.23

  • 3.57

Solved Examples | Q 8 | Page 277

Variance of the data 2, 4, 5, 6, 8, 17 is 23.33. Then variance of 4, 8, 10, 12, 16, 34 will be ______.

  • 23.23

  • 25.33

  • 46.66

  • 93.32

Solved Examples | Q 9 | Page 277

A set of n values x1, x2, ..., xn has standard deviation 6. The standard deviation of n values x1 + k, x2 + k, ..., xn + k will be ______.

  • σ

  • σ + k

  • σ – k

Exercise [Pages 278 - 238]

NCERT Exemplar solutions for Mathematics [English] Class 11 15 Statistics Exercise [Pages 278 - 238]

Short Answer

Exercise | Q 1 | Page 278

Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4
Exercise | Q 2 | Page 278

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4
Exercise | Q 3 | Page 278

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an odd number.

Exercise | Q 4 | Page 278

Calculate the mean deviation about the mean of the set of first n natural numbers when n is an even number.

Exercise | Q 5 | Page 278

Find the standard deviation of the first n natural numbers.

Exercise | Q 6 | Page 278

The mean and standard deviation of some data for the time taken to complete a test are calculated with the following results:
Number of observations = 25, mean = 18.2 seconds, standard deviation = 3.25 seconds. Further, another set of 15 observations x1, x2, ..., x15, also in seconds, is now available and we have `sum_(i = 1)^15 x_i` = 279 and `sum_(i  = 1)^15 x^2` = 5524. Calculate the standard derivation based on all 40 observations.

Exercise | Q 7 | Page 278

The mean and standard deviation of a set of n1 observations are `barx_1` and s1, respectively while the mean and standard deviation of another set of n2 observations are `barx_2` and  s2, respectively. Show that the standard deviation of the combined set of (n1 + n2) observations is given by

S.D. = `sqrt((n_1(s_1)^2 + n_2(s_2)^2)/(n_1 + n_2) + (n_1n_2 (barx_1 - barx_2)^2)/(n_1 + n_2)^2)`

Exercise | Q 8 | Page 279

Two sets each of 20 observations, have the same standard derivation 5. The first set has a mean 17 and the second a mean 22. Determine the standard deviation of the set obtained by combining the given two sets.

Exercise | Q 9 | Page 279

The frequency distribution:

`x` A 2A 3A 4A 5A 6A
`f` 2 1 1 1 1 1

where A is a positive integer, has a variance of 160. Determine the value of A.

Exercise | Q 10 | Page 279

For the frequency distribution:

`x` 2 3 4 5 6 7
`f` 4 9 16 14 11 6

Find the standard deviation.

Exercise | Q 11 | Page 279

There are 60 students in a class. The following is the frequency distribution of the marks obtained by the students in a test.

Marks 0 1 2 3 4 5
Frequency x – 2 x x2 (x + 1)2 2x x + 1

where x is a positive integer. Determine the mean and standard deviation of the marks.

Exercise | Q 12 | Page 279

The mean life of a sample of 60 bulbs was 650 hours and the standard deviation was 8 hours. A second sample of 80 bulbs has a mean life of 660 hours and standard deviation 7 hours. Find the overall standard deviation.

Exercise | Q 13 | Page 279

Mean and standard deviation of 100 items are 50 and 4, respectively. Find the sum of all the item and the sum of the squares of the items.

Exercise | Q 14 | Page 279

If for distribution `sum(x - 5)` = 3, `sum(x - 5)^2` = 43 and total number of items is 18. Find the mean and standard deviation.

Exercise | Q 15 | Page 279

Find the mean and variance of the frequency distribution given below:

`x` 1 ≤ x < 3 3 ≤ x < 5 5 ≤ x < 7 7 ≤ x < 10
`f` 6 4 5 1

Long Answer

Exercise | Q 16 | Page 280

Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2
Exercise | Q 17 | Page 280

Calculate the mean deviation from the median of the following data:

Class interval 0 – 6 6 – 12 12 – 18 18 – 24 24 – 30
Frequency 4 5 3 6 2
Exercise | Q 18 | Page 280

Determine the mean and standard deviation for the following distribution:

Marks 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
Frequency 1 6 6 8 8 2 2 3 0 2 1 0 0 0 1
Exercise | Q 19 | Page 280

The weights of coffee in 70 jars is shown in the following table:

Weight
(in grams)
Frequency
200 – 201 13
201 – 202 27
202 – 203 18
203 – 204 10
204 – 205 1
205 – 206 1

Determine variance and standard deviation of the above distribution.

Exercise | Q 20 | Page 280

Determine mean and standard deviation of first n terms of an A.P. whose first term is a and common difference is d.

Exercise | Q 21 | Page 281

Following are the marks obtained, out of 100, by two students Ravi and Hashina in 10 tests.

Ravi 25 50 45 30 70 42 36 48 35 60
Hashina 10 70 50 20 95 55 42 60 48 80

Who is more intelligent and who is more consistent?

Exercise | Q 22 | Page 281

Mean and standard deviation of 100 observations were found to be 40 and 10, respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.

Exercise | Q 23 | Page 281

While calculating the mean and variance of 10 readings, a student wrongly used the reading 52 for the correct reading 25. He obtained the mean and variance as 45 and 16 respectively. Find the correct mean and the variance.

Objective Type Questions from 24 to 39

Exercise | Q 24 | Page 281

The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is ______.

  • 2

  • 2.57

  • 3

  • 3.75

Exercise | Q 25 | Page 281

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.

  • `sum_(i = 1)^n (x_i - barx)`

  • `1/n sum_(i = 1)^n |x_i - barx|`

  • `sum_(i = 1)^n (x_i - barx)^2`

  • `1/n sum_(i = 1)^n (x_i - barx)^2`

Exercise | Q 26 | Page 281

When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.

  • 178

  • 179

  • 220

  • 356

Exercise | Q 27 | Page 281

Following are the marks obtained by 9 students in a mathematics test: 50, 69, 20, 33, 53, 39, 40, 65, 59

The mean deviation from the median is ______.

  • 9

  • 10.5

  • 12.67

  • 14.76

Exercise | Q 28 | Page 282

The standard deviation of the data 6, 5, 9, 13, 12, 8, 10 is ______.

  • `sqrt(52/7)`

  • `52/7`

  • `sqrt(6)`

  • 6

Exercise | Q 29 | Page 282

Let x1, x2, ..., xn be n observations and `barx` be their arithmetic mean. The formula for the standard deviation is given by ______.

  • (x_i - barx)^2`

  • `(x_i - barx)^2/n`

  • `sqrt((x_i - barx)^2/n`

  • `sqrt(x^2/n + barx^2)`

Exercise | Q 30 | Page 282

The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.

  • 50000

  • 250000

  • 252500

  • 255000

Exercise | Q 31 | Page 282

Let a, b, c, d, e be the observations with mean m and standard deviation s. The standard deviation of the observations a + k, b + k, c + k, d + k, e + k is ______.

  • s

  • ks

  • s + k

  • `s/k`

Exercise | Q 32 | Page 282

Let x1, x2, x3, x4, x5 be the observations with mean m and standard deviation s. The standard deviation of the observations kx1, kx2, kx3, kx4, kx5 is ______.

  • k + s

  • `s/k`

  • ks

  • s

Exercise | Q 33 | Page 282

Let x1, x2, ... xn be n observations. Let wi = lxi + k for i = 1, 2, ...n, where l and k are constants. If the mean of xi’s is 48 and their standard deviation is 12, the mean of wi’s is 55 and standard deviation of wi’s is 15, the values of l and k should be ______.

  • l = 1.25, k = – 5

  • l = – 1.25, k = 5

  • l = 2.5, k = – 5

  • l = 2.5, k = 5

Exercise | Q 34 | Page 282

Standard deviations for first 10 natural numbers is ______.

  • 5.5

  • 3.87

  • 2.97

  • 2.87

Exercise | Q 35 | Page 282

Consider the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. If 1 is added to each number, the variance of the numbers so obtained is ______.

  • 6.5

  • 2.87

  • 3.87

  • 8.25

Exercise | Q 36 | Page 283

Consider the first 10 positive integers. If we multiply each number by –1 and then add 1 to each number, the variance of the numbers so obtained is ______.

  • 8.25

  • 6.5

  • 3.87

  • 2.87

Exercise | Q 37 | Page 283

The following information relates to a sample of size 60 `sumx^2` = 18000 and `sumx` = 960, then the variance is ______.

  • 6.63

  • 16

  • 22

  • 44

Exercise | Q 38 | Page 283

Coefficient of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25 respectively. Difference of their standard deviation is ______.

  • 0

  • 1

  • 1.5

  • 2.5

Exercise | Q 39 | Page 283

The standard deviation of some temperature data in °C is 5. If the data were converted into ºF, the variance would be ______.

  • 81

  • 57

  • 36

  • 25

Fill in the blanks 40 to 46

Exercise | Q 40 | Page 283

Coefficient of variation = `.../"Mean" xx 100`

Exercise | Q 41 | Page 283

If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`

Exercise | Q 42 | Page 283

If the variance of a data is 121, then the standard deviation of the data is ______.

Exercise | Q 43 | Page 283

The standard deviation of a data is ______ of any change in orgin, but is ______ on the change of scale.

Exercise | Q 44 | Page 238

The sum of squares of the deviations of the values of the variable is ______ when taken about their arithmetic mean.

Exercise | Q 45 | Page 238

The mean deviation of the data is ______ when measured from the median.

Exercise | Q 46 | Page 238

The standard deviation is ______to the mean deviation taken from the arithmetic mean.

Solutions for 15: Statistics

Solved ExamplesExercise
NCERT Exemplar solutions for Mathematics [English] Class 11 chapter 15 - Statistics - Shaalaa.com

NCERT Exemplar solutions for Mathematics [English] Class 11 chapter 15 - Statistics

Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 11 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT Exemplar solutions for Mathematics Mathematics [English] Class 11 CBSE 15 (Statistics) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT Exemplar textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 11 chapter 15 Statistics are Central Tendency - Median, Measures of Dispersion, Concept of Range, Mean Deviation, Introduction of Variance and Standard Deviation, Standard Deviation, Standard Deviation of a Discrete Frequency Distribution, Standard Deviation of a Continuous Frequency Distribution, Shortcut Method to Find Variance and Standard Deviation, Introduction of Analysis of Frequency Distributions, Comparison of Two Frequency Distributions with Same Mean, Statistics Concept, Central Tendency - Mean, Measures of Dispersion - Quartile Deviation, Concept of Mode, Standard Deviation - by Short Cut Method.

Using NCERT Exemplar Mathematics [English] Class 11 solutions Statistics exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Exemplar Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 11 students prefer NCERT Exemplar Textbook Solutions to score more in exams.

Get the free view of Chapter 15, Statistics Mathematics [English] Class 11 additional questions for Mathematics Mathematics [English] Class 11 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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