हिंदी

Mean deviation for n observations x1, x2, ..., xn from their mean x¯ is given by ______. - Mathematics

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प्रश्न

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by ______.

विकल्प

  • `sum_(i = 1)^n (x_i - barx)`

  • `1/n sum_(i = 1)^n |x_i - barx|`

  • `sum_(i = 1)^n (x_i - barx)^2`

  • `1/n sum_(i = 1)^n (x_i - barx)^2`

MCQ
रिक्त स्थान भरें

उत्तर

Mean deviation for n observations x1, x2, ..., xn from their mean `barx` is given by `1/n sum_(i = 1)^n |x_i - barx|`.

Explanation:

 M.D. = `1/n sum_(i = 1)^n |x_i - barx|`

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अध्याय 15: Statistics - Exercise [पृष्ठ २८१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 15 Statistics
Exercise | Q 25 | पृष्ठ २८१

वीडियो ट्यूटोरियलVIEW ALL [1]

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