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प्रश्न
For a chemical reaction rate law is, rate = k[A]2[B]. If [A] is doubled at constant [B], the rate of reaction ______.
विकल्प
increases by a factor of 8
increases by a factor of 4
increases by a factor of 3
increases by a factor of 2
MCQ
रिक्त स्थान भरें
उत्तर
For a chemical reaction rate law is, rate = k[A]2[B]. If [A] is doubled at constant [B], the rate of reaction increases by a factor of 4.
Explanation:
Given,
Initial rate = k[A]2[B]
If [A]1 = 2[A]
Rate k = [2A]2 [B] = 4k[A]2 [B]
Thus, if the concentration of A, [A] is doubled and that of [B] is constant, then initial rate increases by a factor of 4.
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Rate of Reaction and Reactant Concentration
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