Question

For a chemical reaction rate law is, rate = k[A]²[B]. If [A] is doubled at constant [B], the rate of reaction ______.

Options

• increases by a factor of 8

• increases by a factor of 4

• increases by a factor of 3

• increases by a factor of 2

Answer 1

For a chemical reaction rate law is, rate = k[A]²[B]. If [A] is doubled at constant [B], the rate of reaction increases by a factor of 4.

Explanation:

Given,

Initial rate = k[A]²[B]

If [A]¹ = 2[A]

Rate k = [2A]² [B] = 4k[A]² [B]

Thus, if the concentration of A, [A] is doubled and that of [B] is constant, then initial rate increases by a factor of 4.