Question

For a chemical reaction, A→ products, the rate of reaction doubles when the concentration of
‘A’ is increased by a factor of 4, the order of reaction is

(A) 2

(B) 0.5

(C) 4

(D) 1

Answer 1

(B) 0.5

Rate₁ = k[A]^x …(i)
Rate₂ = k4^x[A]^x …(ii)
dividing (ii) by (i)

Rate₂/Rate₁=4^X

but Rate2 = 2Rate1 (given)

2Rate₁/Rate₁=4^X

2=4^X

x = 1/2 or 0.5