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प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x - (5 - y) = 7
उत्तर
First draw the graph as follows:
This is an right triangle.
Thus the area of the triangle will be:
= `(1)/(2) xx "base" xx "altitude"`
= `(1)/(2) xx 4 xx 12`
= 24 sq.units
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 3
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y - 2 = 0
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3y + 5 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the equation given below:
2x - 5y = 10
Draw the graph of the equation 3x - 4y = 12.
Use the graph drawn to find:
(i) y1, the value of y, when x = 4.
(ii) y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 5x + 2y = 16
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
