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प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x - (5 - y) = 7
उत्तर
First draw the graph as follows:
This is an right triangle.
Thus the area of the triangle will be:
= `(1)/(2) xx "base" xx "altitude"`
= `(1)/(2) xx 4 xx 12`
= 24 sq.units
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संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
x - 5 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
