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प्रश्न
Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
उत्तर
We have
2x - 3y = 15
⇒ -3y = 15 - 2x
⇒ 3y = 2x - 15
⇒ y = `(2x - 15)/(3)`
When x = -2
⇒ y = `-(19)/(3)`
= -6.34
When x = 0
⇒ y = `-(15)/(3)` = -5
When x = 2
⇒ y = `-(11)/(3)` = -3.66
| x | -2 | -1 | 0 | 1 | 2 |
| y | -6.34 | -5.66 | -5 | -4.34 | -3.66 |
Thus ordered pairs of 2x - 3y = 15 are {(-2, -6.34), (-1, -5.66), (0, -5),(1, - 4.34), (2, -3.66)}. Hence graph is a below.
(i) x, when y = 3
From graph we find that x = 12, when y = 3
(ii) y, when x = 0
Fro graph we find that y = -5, when x = 0.
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