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प्रश्न
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
उत्तर
The equation will become:
2x - 3y = 8
First prepare a table as follows:
| x | -1 | 0 | 1 |
| y | `-(10)/(3)` | `-(8)/(3)` | -2 |
Thus the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
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Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
