Advertisements
Advertisements
प्रश्न
Given:
A = {x : 11x – 5 > 7x + 3, x ∈ R} and
B = {x : 18x – 9 ≥ 15 + 12x, x ∈ R}.
Find the range of set A ∩ B and represent it on the number line.
उत्तर
A = {x : 11x – 5 > 7x + 3, x ∈ R}
= {x : 4x > 8, x ∈ R}
= {x : x > 2, x ∈ R}
B = {x : 18x – 9 ≥ 15 + 12x, x ∈ R}
= {x : 6x ≥ 24, x ∈ R}
= {x : x ≥ 4, x ∈ R}
A ∩ B = {x : x ≥ 4, x ∈ R}
It can be represented on number line as:
APPEARS IN
संबंधित प्रश्न
Represent the following inequalities on real number line:
2(2x – 3) ≤ 6
Use the real number line to find the range of values of x for which:
x > 3 and 0 < x < 6
P is the solution set of 7x – 2 > 4x + 1 and Q is the solution set of 9x – 45 ≥ 5(x – 5); where x ∈ R. Represent:
- P ∩ Q
- P – Q
- P ∩ Q’ on the different number of lines.
Graph the solution set for each inequality:
x ≥ - 3
Graph the solution set for each inequality:
-3≤ x ≤3.
Solve the following inequalities and represent the solution on a number line:
`(2x + 5)/(4) > (4 - 3x)/(6)`
If x ∈ Z, solve 2 + 4x < 2x – 5 ≤ 3x. Also represent its solution on the number line.
Solve the inequation – 3 ≤ 3 – 2x < 9, x ∈ R. Represent your solution on a number line.
Solve the inequation : `-2(1)/(2) + 2x ≤ (4x)/(3) ≤ (4)/(3) + 2x, x ∈ "W"`. Graph the solution set on the number line.
The following number line represents: