Advertisements
Advertisements
प्रश्न
Given:
A = {x : 11x – 5 > 7x + 3, x ∈ R} and
B = {x : 18x – 9 ≥ 15 + 12x, x ∈ R}.
Find the range of set A ∩ B and represent it on the number line.
उत्तर
A = {x : 11x – 5 > 7x + 3, x ∈ R}
= {x : 4x > 8, x ∈ R}
= {x : x > 2, x ∈ R}
B = {x : 18x – 9 ≥ 15 + 12x, x ∈ R}
= {x : 6x ≥ 24, x ∈ R}
= {x : x ≥ 4, x ∈ R}
A ∩ B = {x : x ≥ 4, x ∈ R}
It can be represented on number line as:
APPEARS IN
संबंधित प्रश्न
Represent the following inequalities on real number line:
2x – 1 < 5
Use the real number line to find the range of values of x for which:
–1 < x ≤ 6 and –2 ≤ x ≤ 3
Given that x ∈ I. solve the inequation and graph the solution on the number line:
`3 >= (x - 4)/2 + x/3 >= 2`
Solve the following linear in-equation and graph the solution set on a real number line:
2x - 11≤ 7 - 3x, x ∈ N
Solve the following in equation and write the solution set:
13x - 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.
Solve the following inequation and represent the solution set on a number line.
`-8 1/2 < -1/2 - 4x ≤ 7 1/2, x ∈ I`
Solve the equation and represent the solution set on the number line.
`-3 + x ≤ (8x)/(3)+ 2 ≤ (14)/(3)+ 2x`, where x ∈ I
Solve the following inequalities and represent the solution on a number line:
3(x - 2) > 1
Solve `(3x)/(5) - (2x - 1)/(3)` > 1, x ∈ R and represent the solution set on the number line.
Solve the given inequation and graph the solution on the number line : 2y – 3 < y + 1 ≤ 4y + 7; y ∈ R.
