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प्रश्न
Find the set of values of x, satisfying:
`7x + 3 >= 3x - 5` and `x/4 - 5 <= 5/4 -x`, where x ∈ N
उत्तर
`7x + 3 >= 3x - 5`
`4x >= -8`
`x >= -2`
`x/4 - 5 <= 5/4 - x`
`x/4 + x <= 5/4 + 5`
`(5x)/4 <=25/4`
`x <= 5`
Since, x ∈ N
∴ Solution set = {1, 2, 3, 4, 5}
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संबंधित प्रश्न
Solve the following inequation, write the solution set and represent it on the number line `-x/3 <= x/2 - 1 1/3 < 1/6, x ∈ R`
Represent the following inequalities on real number line:
3x + 1 ≥ – 5
Represent the following inequalities on real number line:
2(2x – 3) ≤ 6
Represent the solution of the following inequalities on the real number line:
7 – x ≤ 2 – 6x
The diagram represents two inequations A and B on real number lines:
- Write down A and B in set builder notation.
- Represent A ∪ B and A ∩ B' on two different number lines.
Use the real number line to find the range of values of x for which:
x < 0 and –3 ≤ x < 1
Solve the inequation:
`-2 1/2 + 2x <= (4x)/5 <= 4/3 + 2x, x ∈ W`.
Graph the solution set on the number line.
Solve the equation and represent the solution set on the number line.
`-3 + x ≤ (8x)/(3)+ 2 ≤ (14)/(3)+ 2x`, where x ∈ I
Solve the following inequalities and represent the solution on a number line:
`(2x + 5)/(4) > (4 - 3x)/(6)`
For the inequations A and B [as given above in part (d)], A ∪ B is:
