Advertisements
Advertisements
प्रश्न
Given that `sqrt(3)` is irrational, prove that `5 + 2sqrt(3)` is irrational.
उत्तर
Let us assume `5 + 2sqrt(3)` is rational, then it must be in the form of `p/q` where p and q are co-prime integers and q ≠ 0
i.e. `5 + 2sqrt(3) = p/q`
So `sqrt(3) = (p - 5q)/(2q)` ......(i)
Since p, q, 5 and 2 are integers and q ≠ 0, RHS of equation (i) is rational. But LHS of (i) is `sqrt(3)` which is irrational. This is not possible.
This contradiction has arisen due to our wrong assumption that `5 + 2sqrt(3)` is rational.
So, `5 + 2sqrt(3)` is irrational.
संबंधित प्रश्न
Classify the following number as rational or irrational:
`sqrt23`
Examine, whether the following number are rational or irrational:
`sqrt7`
Examine, whether the following number are rational or irrational:
`sqrt5-2`
Give an example of two irrational numbers whose:
quotient is a rational number.
Write the following in ascending order:
`5sqrt(7), 7sqrt(5) and 6sqrt(2)`
`(6 + 5sqrt3) - (4 - 3 sqrt3)` is ______.
The product of any two irrational numbers is ______.
Which of the following is irrational?
Find whether the variable x represents a rational or an irrational number:
x2 = 5
Insert a rational number and an irrational number between the following:
6.375289 and 6.375738