Advertisements
Advertisements
प्रश्न
Given x ∈ {real numbers}, find the range of values of x for which –5 ≤ 2x – 3 < x + 2 and represent it on a number line.
उत्तर
–5 ≤ 2x – 3 < x + 2
–5 ≤ 2x – 3 and 2x – 3 < x + 2
–2 ≤ 2x and x < 5
–1 ≤ x and x < 5
∴ Required range is –1 ≤ x < 5
The required graph is
APPEARS IN
संबंधित प्रश्न
`-5x >= 15 => x >= -3`
If a > b, then a + c > b + c
If a > b, then `a/c < b/c`
If the replacement set is the set of real numbers, solve:
8 – 3x ≤ 20
Solve for x in the following in-equation, if the replacement set is R;
3x >12
Solve for x in the following in-equation, if the replacement set is R;
2x - 7 ≥ 5x + 8
Solve for x : 6 - 10x < 36, x ∈ {-3, -2, -1, O, 1, 2}
If x + 17 ≤ 4x + 9, find the smallest value of x, when:
x ∈ Z
Solve the following inequation and graph the solution set,
2x - 5 ≤ 5x + 4 < 11n ∈ R.
The maximum value of x for the inequation 4x ≤ 12 + x is ______.