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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Graph the following quadratic equation and state their nature of solution x2 – 9x + 20 = 0 - Mathematics

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प्रश्न

Graph the following quadratic equation and state their nature of solution

x2 – 9x + 20 = 0

आलेख
योग

उत्तर

Let y = x2 – 9x + 20

(i) Prepare the table of values for y = x2 – 9x + 20

x – 3 – 2 – 1 0 1 2 3 4 5 6
x2 9 4 1 0 1 4 9 16 25 36
– 9x 27 18 9 0 – 9 – 18 – 27 – 36 – 45 – 54
20 20 20 20 20 20 20 20 20 20 20
y 56 42 30 20 12 6 2 0 0 2

(ii) Plot the points (– 1, 30) (0, 20) (1, 12) (2, 6) (3, 2), (4, 0), (5, 0), (6, 2) ........(omit the high value)

(iii) Join the points by a free hand smooth curve.

(iv) The roots of the equation are the X-coordinates of the intersecting points of the curve with X-axis (4, 0) and (5, 0)

There are two points of intersection with the X-axis at 4 and 5. The solution set is 4 and 5.

The quadratic equation has real and unequal roots.

(v) Since there is two point of intersection with X-axis .......(different solution)

∴ The equation x2 – 9x + 20 = 0 has real and unequal roots.

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Quadratic Graphs
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अध्याय 3: Algebra - Exercise 3.15 [पृष्ठ १३७]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.15 | Q 1. (i) | पृष्ठ १३७
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