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Question
Graph the following quadratic equation and state their nature of solution
x2 – 9x + 20 = 0
Solution
Let y = x2 – 9x + 20
(i) Prepare the table of values for y = x2 – 9x + 20
x | – 3 | – 2 | – 1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
x2 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 | 25 | 36 |
– 9x | 27 | 18 | 9 | 0 | – 9 | – 18 | – 27 | – 36 | – 45 | – 54 |
20 | 20 | 20 | 20 | 20 | 20 | 20 | 20 | 20 | 20 | 20 |
y | 56 | 42 | 30 | 20 | 12 | 6 | 2 | 0 | 0 | 2 |
(ii) Plot the points (– 1, 30) (0, 20) (1, 12) (2, 6) (3, 2), (4, 0), (5, 0), (6, 2) ........(omit the high value)
(iii) Join the points by a free hand smooth curve.
(iv) The roots of the equation are the X-coordinates of the intersecting points of the curve with X-axis (4, 0) and (5, 0)
There are two points of intersection with the X-axis at 4 and 5. The solution set is 4 and 5.
The quadratic equation has real and unequal roots.
(v) Since there is two point of intersection with X-axis .......(different solution)
∴ The equation x2 – 9x + 20 = 0 has real and unequal roots.
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