Advertisements
Advertisements
Question
Draw the graph of y = x2 – 4 and hence solve x2 – x – 12 = 0
Solution
(i) Draw the graph of y = x2 – 4 by preparing the table of values as below.
x | – 4 | – 3 | – 2 | – 1 | 0 | 1 | 2 | 3 | 4 |
x2 | 16 | 9 | 4 | 1 | 0 | 1 | 4 | 9 | 16 |
– 4 | – 4 | – 4 | – 4 | – 4 | – 4 | – 4 | – 4 | – 4 | – 4 |
y | 12 | 5 | 0 | – 3 | – 4 | – 3 | 0 | 5 | 12 |
(ii) Plot the points for the ordered pairs (– 4, 12) (– 3, 5) (– 2, 0) (– 1, – 3) (0, – 4) (1, – 3), (2, 0), (3, 5) and (4, 12). Draw the curve with a suitable scale.
(iii) To solve x2 – x – 12 = 0 subtract x2 – x – 12 from y = x2 – 4
y = x2 – 0 – 4
0 = x2 – x – 12
(–) (+) (–)
y = x + 8
The equation y = x + 8 represents a straight line. Prepare a table for y = x + 8
x | – 3 | – 1 | 0 | 2 | 4 |
y | 5 | 7 | 8 | 10 | 12 |
(iv) Mark the point of intersection of the curve and the straight line is (– 3, 5) and (4, 12)
∴ The solution set is (– 3, 4) for x2 – x – 12 = 0.
APPEARS IN
RELATED QUESTIONS
Graph the following quadratic equation and state their nature of solution
x2 – 9x + 20 = 0
Graph the following quadratic equation and state their nature of solution
x2 – 6x + 9 = 0
Graph the following quadratic equation and state their nature of solution
(2x – 3) (x + 2) = 0
Draw the graph of y = x2 + 3x – 4 and hence use it to solve x2 + 3x – 4 = 0
Draw the graph of y = x2 – 5x – 6 and hence solve x2 – 5x – 14 = 0
Draw the graph of y = 2x2 – 3x – 5 and hence solve 2x2 – 4x – 6 = 0
Draw the graph of y = (x – 1) (x + 3) and hence solve x2 – x – 6 = 0
The solution of the system x + y – 3z = – 6, – 7y + 7z = 7, 3z = 9 is
`y^2 + 1/y^2` is not equal to
The solution of (2x – 1)2 = 9 is equal to